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Output power in an electromagnetic waveguide completely open in the middle.
Posted Mar 6, 2024, 5:48 p.m. EST Electromagnetics, Results & Visualization Version 6.0 1 Reply
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I am buiding a electromagnetic waveguide with two horns and two rectangular ports (port 1 is the input power with a value of 0.01W) with impedance boundary condition and perfectly matched layers. The major purpose is to know what is the output power in the port 2 in Watt units.
I think that it is:
Output power=(abs(emw.S21)^2) * (Input power)
But I do not know if this is correct.
Please refer to the attached image for more geometry details. I would appreciate your help.
Thank you!
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Hmm. This will probably work if you don't have errors in your model (you didn't post your .mph file, so I can't be sure since I can't see all your other settings). Note that you could simply plot emw.S21dB in post-processing. 0dB means all (100%) the power gets thru, while -3dB means ~half the power (10^-0.3) gets thru, etc. You might want to take a look at emw.S11dB too, to get an idea of how much reflection occurs. Also, I presume you are using the impedance boundary conditions on the waveguide horns (to represent their finite conductivities), and not the ports.
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